MySQL 查询今天、昨天、7 天、近 30 天、本月、上一月 数据

Mysql tytrock ⋅ 于 2016-11-28 08:31:41 ⋅ 1939 阅读

今天
select * from 表名 where to_days(时间字段名) = to_days(now());

昨天
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

7天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

查询本季度数据
select * from 表名 where QUARTER(create_date)=QUARTER(now());
查询上季度数据
select * from 表名 where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
查询本年数据
select * from 表名 where YEAR(create_date)=YEAR(NOW());
查询上年数据
select * from 表名 where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查询上个月的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from user where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select * from user where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select * from [ user ] where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now()) and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select * from [ user ] where pudate between 上月最后一天 and 下月第一天 where date(regdate) = curdate();

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( ) FROMt_scoreWHERE 1 LIMIT 0 , 30


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